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Heat Capacity

At 27∘ C, t...

Question

At $27^{\circ} C$ , the $K_{p}$ value for the reaction $P C l_{5} ⇋ P C l_{3} + C l_{2}$ is 0.65. Its $K_{c}$ is:

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0.65

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0.2

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0.026

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Solution

The correct option is D 0.026
The relationship between $K_{p}$ and $K_{c}$ is $K_{p} = K_{c} (R T)^{Δ n}$ .

For the reaction $P C l_{5} ⇋ P C l_{3} + C l_{2}$ , the value of $Δ n$ is $1 + 1 - 1 = 1$ .

Substitute this value in the above expression:

$K_{p} = K_{c} (R T)^{Δ n} = K_{c} (R T)^{1}$ .

But $K_{p} = 0.65, R = 0.082 L atm /mol. K, T = 27 + 273 = 300 K$ .

Substitute values in the above expression:

$0.65 = K_{c} (0.082 \times 300)^{1}$

$K_{c} = 0.026$ .

Hence, option D is correct.

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At 27∘C, the Kp value for the reaction PCl5⇋PCl3+Cl2 is 0.65. Its Kc is:

At $27^{\circ} C$ , the $K_{p}$ value for the reaction $P C l_{5} ⇋ P C l_{3} + C l_{2}$ is 0.65. Its $K_{c}$ is: