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Question

At 298 K, the conductivity of a saturated solution of AgCl in water is 2.6×106S cm1. Its solubility product at 298 K (given : λ(Ag+)=63.0S cm2mol1,λ(Cl)=67.0 S cm2mol1)



Your Answer
A

2.0×105M2

Correct Answer
B

4.0×1010M2

Your Answer
C

4.0×1016M2

Your Answer
D

2×108M2


Solution

The correct option is B

4.0×1010M2


Solubility S=1000kλAgCl=1000×2.6×106λAg+λCl=2.6×10363+67=2×105mol L1;Ksp=S2

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