Question

# At a temperature '$$T$$' $$K$$, the pressure of 4.0 $$g$$ of argon in a bulb is $$p$$.  The bulb is put in a bath having temperature higher by 50 $$K$$ than the first one. 0.8 $$g$$ of argon gas had to be removed to maintain original pressure. The temperature $$T$$ is equal to:

A
510 K
B
200 K
C
100 K
D
73 K

Solution

## The correct option is C 200 $$K$$As we know, $$PV=nRT$$.Here, initially $$P$$ & $$V$$ are equal to final $$P$$ & $$V$$ so, $$nRT$$ (initial) $$=nRT$$ (final).$$(4/x)RT=(4-0.8)/x \times R(T+50)$$$$T=200$$ $$K$$.Chemistry

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