CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

At a temperature 'T' K, the pressure of 4.0 g of argon in a bulb is p. The bulb is put in a bath having temperature higher by 50 K than the first one. 0.8 g of argon gas had to be removed to maintain original pressure. The temperature T is equal to:

A
510 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
200 K
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
100 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
73 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 200 K
As we know, PV=nRT.
Here, initially P & V are equal to final P & V so, nRT (initial) =nRT (final).
(4/x)RT=(40.8)/x×R(T+50)
T=200 K.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Ideal Gas Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon