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Question

At a temperature '$$T$$' $$K$$, the pressure of 4.0 $$g$$ of argon in a bulb is $$p$$.  The bulb is put in a bath having temperature higher by 50 $$K$$ than the first one. 0.8 $$g$$ of argon gas had to be removed to maintain original pressure. The temperature $$T$$ is equal to:


A
510 K
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B
200 K
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C
100 K
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D
73 K
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Solution

The correct option is C 200 $$K$$
As we know, $$PV=nRT$$.
Here, initially $$P$$ & $$V$$ are equal to final $$P$$ & $$V$$ so, $$nRT$$ (initial) $$=nRT$$ (final).
$$(4/x)RT=(4-0.8)/x \times R(T+50)$$
$$T=200$$ $$K$$.

Chemistry

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