Question

# At N.T.P the volume of a gas is found to be $$273mL$$. What will be the volume of this gas at $$600mm$$ $$Hg$$ and $${273}^{o}C$$?

A
391.8mL
B
380mL
C
644mL
D
750mL

Solution

## The correct option is C $$644mL$$Solution:NTP = 1 atm at 293.15 Kelvin Given $$P_1=600$$ mm Hg$$=0.79$$ atm                   $$(1 atm=760 mm Hg$$)$$\dfrac{PV}{T}$$ = $$\dfrac { { P }_{ 1 }{ V }_{ 1 } }{ { T }_{ 1 } }$$$$\dfrac{1atm\times 273mL}{293K}=\dfrac{0.79atm\times xmL}{546K}$$$$\dfrac{273 \times 546}{293\times0.79}= x$$$$x=643.96\approx 644$$ mL Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More