At N.T.P the volume of a gas is found to be $273 m L$ . What will be the volume of this gas at $600 m m$ $H g$ and $273^{o} C$ ?

391.8 m L

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380 m L

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644 m L

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750 m L

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Solution

The correct option is C $644 m L$
Solution:
NTP = 1 atm at 293.15 Kelvin
Given $P_{1} = 600$ mm Hg $= 0.79$ atm $(1 a t m = 760 m m H g$ )
$\frac{P V}{T}$ = $\frac{P_{1} V_{1}}{T_{1}}$
$\frac{1 a t m \times 273 m L}{293 K} = \frac{0.79 a t m \times x m L}{546 K}$
$\frac{273 \times 546}{293 \times 0.79} = x$
$x = 643.96 \approx 644$ mL

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