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Question

At N.T.P the volume of a gas is found to be $$273mL$$. What will be the volume of this gas at $$600mm$$ $$Hg$$ and $${273}^{o}C$$?


A
391.8mL
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B
380mL
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C
644mL
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D
750mL
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Solution

The correct option is C $$644mL$$
Solution:
NTP = 1 atm at 293.15 Kelvin 
Given $$P_1=600$$ mm Hg$$=0.79$$ atm                   $$(1 atm=760 mm Hg$$)
$$\dfrac{PV}{T}$$ = $$\dfrac { { P }_{ 1 }{ V }_{ 1 } }{ { T }_{ 1 } } $$
$$\dfrac{1atm\times 273mL}{293K}=\dfrac{0.79atm\times xmL}{546K}$$
$$\dfrac{273 \times 546}{293\times0.79}= x$$
$$x=643.96\approx 644$$ mL 

Chemistry

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