At resonance, a series LCR circuit is -

predominantly capacitive

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predominantly inductive

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purely resistive

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None of these

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Solution

The correct option is C purely resistive
For a series LCR circuit, at resonance, $X_{L} = X_{C}$ and $Z = R$ . Therefore, the circuit is purely resistive.

Hence, option $(C)$ is the correct answer.

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Similar questions

For a series LCR circuit at resonance, the statement which is not true is:

L C R

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