Question

# At room temperature, copper has free electron density of $$8.4 \times 10^{28} m^{-3}$$. The electron drift velocity in a copper conductor of cross-sectional area of $$10^{-6}m^2$$ and carrying a current of 5.4 A, will be

A
4 ms1
B
0.4 ms1
C
4 cms1
D
0.4 mms1

Solution

## The correct option is D $$0.4 \ mms^{-1}$$Drift velocity is the average uniform velocity attained by free electrons inside metal by the application of an electric field which is responsible for current through it.Drift velocity in a conductor is given as:$$\Rightarrow v_d=\dfrac{i}{neA}$$          $$=\dfrac{5.4}{8.4\times 10^{28}\times 1.6\times 10^{-19}\times 10^{-6}}m/s$$          $$=4\times 10^{-4}\ m/s$$          $$=0.4\ m m/s$$Physics

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