0.75 mol of solid X4 and 2 mol of O2 are heated in a closed container to form only one gaseous compound. The ratio of the final pressure at 327∘C to the initial pressure at 27∘C in the flask is?
A
0.75
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B
1
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C
1.5
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D
2
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Solution
The correct option is D 1
Mole atoms of X=0.75×4=3; Mole atoms of O=2×2=4
Hence, the product is X3O4(g)
Initial moles of gaseous reactants, n1=2 (oxygen only)
Final moles of gaseous products, n2=1(X3O4) Hence, P2/P1=n2T2/n1T1=1×6002×300=1 or P2:P1=1:2