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Question

At what temperature, the $$rms$$ velocity of $$O_{2}$$ is equal to $$rms$$ velocity of $$SO_{2}$$ at $$127^{o}C$$:


A
110 K
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B
173 K
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C
200 K
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D
273 K
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Solution

The correct option is C 200 $$K$$
When $$RMS$$ velocities are equal,
$$\displaystyle \frac{T_{1}}{T_{2}}={\frac{M_{1}}{M_{2}}}$$
$$\displaystyle \frac{T_{O_2}}{T_{SO_2}}=  \frac {T_{O_2}}{400} ={\frac{32}{64}}$$
Thus, $$T_{O_2} = 200 \:K$$ 

Chemistry

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