At what time after throwing does it hit the plateau??
( $g = 9.8 m / s^{2}$ )

0.9 s

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3.04 s

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4 s

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1 s

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Solution

The correct option is B $3.04 s$
Maximum height of the projectile is given by $H = \frac{u^{2} S i n^{2} θ}{2 g}$
So $H = 900 \times \frac{3}{4} \times \frac{1}{2 g}$ .
$H = 34.43 m e t e r s$
Ball will first go to top then return to height 20 m. Or 14.43 m from top.
So tital time will be $\frac{1}{2} T$ +time taken for u=0 and acceleration=9.8 and displacement =14.43
$\frac{u S i n 60}{g} + \sqrt{\frac{2 \times 14.43}{g}}$ $=> 3.041$
So time taken will be 3.04.

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At what time after throwing does it hit the plateau??(g=9.8 m/s2)

At what time after throwing does it hit the plateau??
( $g = 9.8 m / s^{2}$ )