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Question

Atomic number of Mn. Fe and Co are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamangetic?
(a) [Co(NH3)6]3+
(b) [Mn(CN)6]3
(c) [Fe(CN)6]4
(d) [Fe(CN)6]3

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Solution

Molecular orbital electronic configuration of Co3+ in [Co(NH3)6]3+ is



Number of unpaired electron = 0
Magnetic property = Diamagnetic
Molecular orbital electronic configuration of Mn3+ in [Mn(CN)6]3



Number of unpaired electron = 2
Magnetic property = Paramagnetic
Molecular orbital electronic configuration of Fe2+ in [Fe(CN)6]4 is



Number of unpaired electron = 0
Magnetic property = Diamagnetic
Molecular orbital electronic configuration of Fe2+ in [Fe(CN)6]4 is



Number of unpaired electron = 1
Magnetic property = Paramagnetic
Thus, [Co(NH3)6]3+ and [Fe(CN)6]4 are diamagnetic.
Hence, correct choices are options (a) and (c).






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