Atomic radii of fluorine and neon in angstrom units are, respectively, given by :
A
0.72, 1.60
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B
1.60, 1.60
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C
0.72, 0.72
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D
1.60, 0.72
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Solution
The correct option is A 0.72, 1.60 The radius of flourine is measured using covalent radius whereas that of neon is measured using Van der Waal's radius. It is known that the Van der Waal's radius is greater than the covalent radius. Hence, flourine is smaller than neon. From the options we see that only option A validates this fact.