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Question

Atomic weight of boron is 10.81 and it has two isotopes 105B and 115B in nature would be :

A
19:81
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B
10:11
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C
15:16
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D
81:19
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Solution

The correct option is A 19:81

The nature would be given as

AtomicWeight=(abundance×atomicmass+abundance×atomicmass)100

Letx be the abundance of the105B

(100x)be abundance of115B

So on solving the above equation

10.81=10x+(100x)11100

x=19

We get the abundance ratio is1981


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