Atoms of element B form a ccp lattice and those of the element A occupy 2/3rd of the tetrahedral voids, the formula of the compound is:

A₃B₄

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A₂B₂

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A₂B₃

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A₄B₃

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Solution

The correct option is D
A₄B₃

Number of close packed spheres = n

Number of tetrahedral voids = 2n

Only 2/3 are occupied by the atoms of element A. Hence the formula of the compound is A₄B_3.

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Q7) atoms of an element B forms HCP lattice and those of the elements A occupy 2/3rd of tetrahedral voids derive the formula of the compound

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