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Question

Auto-ionisation of liquid NH3 is

2NH3NH4+NH2
with KNH3=[NH4][NH2]=1030at50oC
Number of atomic ions (NH2), present per mm3 of pure liquied NH3 is:

A
602
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B
301
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C
200
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D
100
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Solution

The correct option is A 602
KNH3=[NH4][NH2]=1030
[NH4]=[NH2]
So [NH2]=1015
So no of ions in mm3 = 1015×No×106=6.02×102=602

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