CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Average lifetime of a hydrogen atom excited to n = 2 state is 10−8 s. Find the number of revolutions made by the electron on the average before it jumps to the ground state.

Open in App
Solution

Frequency of electron (f) is given by
f=me44 02 n3 h3
Time period is given by
T=1fT=4 02 n3 h3me4
Here,
h = Planck's constant
m = Mass of the electron
e = Charge on the electron
ε0= Permittivity of free space
T=4×8.85×10-12×23×6.63×10-3439.10×10-31×1.6×10-164 =12247.735 ×10-19 s
Average life time of hydrogen, t = 10-8 s
Number of revolutions is given by
N=tTN=10-812247.735×10-19
N = 8.2 × 105 revolution

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy Graph Diagram
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon