Question

# Average torque on a projectile of mass $$m$$, initial speed $$u$$ and angle of projection $$\theta$$ between initial and final positions $$P$$ and $$Q$$ about the point of projection is

A
mu2sin2θ2
B
mu2cosθ
C
mu2sinθ
D
mu2cosθ2

Solution

## The correct option is A $$\dfrac {mu^{2}sin2\theta}{2}$$Torque at a general point $$=$$ Horizontal distance covered $$\times$$ m g (as we only take r perpendicular to g) $$\therefore \tau = mg \times u cos \theta t$$ ......(1)$$t =\dfrac{usin \theta}{g}$$ Substituting t in (1), we get $$\tau = \dfrac{mu^2 \sin 2\theta}{2}$$Physics

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