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Question

Ayush starts walking from his house to office . Instead of going to the office directly , he goes to a bank first , from there to his daughter 's school and then reaches the office. what is the extra distance travelled by Ayush in reaching the office ? ( Assume that all distances covered are in straight lines) . If the house is situated at (2,4) , bank at (5,8) , school at (13,14) and office at ( 13,26) and coordinates are in kilometers .

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Solution

The position of the ayush's house is (2, 4) and that of the bank is (5, 8).
The distance between the house and the bank is
d1=5-22+8-42=32+42=9+16=5 units
The position of the the bank is (5, 8) and that of the school is (13, 14).
The distance between the bank and the school is
d2=13-52+14-82=82+62=64+36=10 units
The position of the school is (13, 14) and that of the office is (13, 6)
The distance between the bank and the school is
d3=13-132+26-142=02+122=12 units
Suppose d be the total distance travelled by ayush
d=d1+d2+d3d=5+10+12d=27 km
Now, let D be the shortest distance between ayush house and the office,
D=13-22+26-42=112+222=605 =24.6 km

Thus the extra distance covered by ayush is d − D = 27 − 24.6 = 2.4 km.

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