Question

Question 126 (b)

Architects design many types of buildings. They draw plans for houses, such as the plant shown in the following figure.

An architect wants to install a decorative moulding around the ceilings in the rooms. The decorative moulding costs ₹ 500/ meter.

The carpet costs ₹ 200 per $m^2$. Find the cast of carpeting each room.

Answer 1

For bedroom 1,

Given, length of bedroom 1 = 3.04 m and breadth of bedroom 1 = 3.04 m

$\therefore$ Area of bedroom 1= Length $\times$ Breadth

$\therefore$ Area of bedroom 1 = 3.04 $\times$ 3.04 = 9.2416 sq m $\because$ Cost of carpeting 1 sq m = ₹ 200

$\therefore$ Cost of carpeting 9.2416 $m^2$ = 9.2416 $\times$ 200 = ₹ 1848.32

For bedroom 2,

Given, length of bedroom 2 = 3.04 m

and breadth of bedroom 2 = 2.43 m

$\therefore$ Area of bedroom 2 = Length $\times$ Breadth = 3.04 $\times$ 2.43 = 7.3872 $m^2$

$\therefore$ Cost of carpeting 1 $m^2$ = ₹ 200

$\therefore$ Cost of carpeting 7.3872 $m^2$ = 7.3872 $\times$ 200 = ₹ 1477.44

For living room,

Given, length of living room = 3.81 m and breadth of living room = 7.53 m

$\therefore$ Area of living room = 3.81 $\times$ 7.53 = 28.6893 $m^2$

Cost of carpeting of living room1 $m^2$ = ₹ 200

$\therefore$ Cost of carpeting 28.6893 $m^2$ = Rs. 200 $\times$ 28.6893 = ₹ 5737.86

For dining room,

Given, length of dining room = 5.41 m

and breadth of dining room = 5.48 m

$\because$ Area of dining room = 5.41 $\times$ 5.48 = 29.6468 $m^2$

$\because$ Cost of carpeting 1 $m^2$ = ₹ 200

$\therefore$ Cost of carpeting 29.6468 $m^2$ = 29.6468 $\times$ 200= ₹ 5929.36

For family room,

Given length of family room = 4.57 m

and breadth of family room = 5.48 m

$\therefore$ Area of family room = 5.48 $\times$ 4.57 = 25.0436 $m^2$

So, cost of carpeting family room = 25.0436 $\times$ 200 = ₹ 5008.72