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Question

Balance $$ MnO^-_4 +Fe^{2+} \rightarrow Fe^{3+} + Mn^{2+} $$ in acidic medium by iron electron method.


Solution

$$ MnO_4^- +Fe^{2+} \rightarrow Fe^{3+} +Mn^{2+} $$
$$ [Fe^{2+} \rightarrow Fe^{3+}] \times ......(i) $$
$$ 8H^+ + MnO_4^- > Mn^{2+} + 4H_2O....(i) $$
...(ii) Adding (i) and (iii),we gwt
$$ 5Fe^{2+} + 8H^+ + MnO_4^- \rightarrow Mn^{2+} + 4H_2O+5Fe^{3+} $$

Chemistry

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