Question

Balance the following chemical equations:$$Cu+HNO_{3} \rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O$$

Solution

$$Cu+HNO_{3} \rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O$$Let us first balance, $$'H'$$ and $$'O'$$ on both sides of the equation by inserting $$'4'$$ before $$HNO_{3}$$ in L.H.S. $$'2'$$ before $$NO_{2}$$ and $$2$$ before $$H_{2}O$$ in R.H.S., we get: $$Cu + 4HNO_{3} \rightarrow Cu(NO_{3})_{2} + 2NO_{2}+ 2H_{2}O$$Chemistry

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