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Question

∣ ∣ ∣1aa2bc1bb2ac1cc2ab∣ ∣ ∣=
 
  1. 0
  2. a3+b3+c33abc
  3. 3abc
  4. (a+b+c)3


Solution

The correct option is A 0
∣ ∣ ∣1aa2bc1bb2ac1cc2ab∣ ∣ ∣=∣ ∣ ∣0ab(ab)(a+b+c)0bc(bc)(a+b+c)1cc2ab∣ ∣ ∣
by {R1R1R2R2R2R3=(ab)(bc)∣ ∣01a+b+c01a+b+c1cc2ab∣ ∣=0,{R1R2}.

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