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Question

∣ ∣2c2ccababc2a2a2bbca2b∣ ∣ =

A
(a+b+c)2
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B
(a+b+c)3
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C
(a+b+c)
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D
(a+b+c)4
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Solution

The correct option is A (a+b+c)3
∣ ∣2c2ccababc2a2a2bbca2b∣ ∣
C1C1C2,C2C2C3
=∣ ∣ ∣0(a+b+c)cab(a+b+c)02a(a+b+c)(a+b+c)2b∣ ∣ ∣
=(a+b+c)2∣ ∣01cab102a112b∣ ∣
R3R3+R2
=(a+b+c)2∣ ∣01cab102a012a+2b∣ ∣
=(a+b+c)2[1(2a+2b+cab)]
=(a+b+c)3

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