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Question

sin2θcos2θcos2θsin2θ= _____


Your Answer
A
cos2θ
Correct Answer
B
12(1+cos22θ)
Your Answer
C
12(1sin22θ)
Your Answer
D
12sin22θ

Solution

The correct option is A 12(1+cos22θ)
sin2θcos2θcos2θsin2θ

=sin4θ+cos4θ
=(sin2θ+cos2θ)22sin2θcos2θ
=112sin22θ
=112(1cos22θ)
=12(1+cos22θ)

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