Bleaching of flowers by $C l_{2}$ is permanent while bleaching by $S O_{2}$ is temporary. Why?

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Solution

Bleaching action of $S O_{2}$ : Bleaching by $S O_{2}$ is permanent due to the process of reduction in the sense of moisture.
$S O_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 [H]$ (nascent)
Colour material $+ [H] \to$ Colourless $a i r - \to$ Colour
Bleaching action of $C l_{2}$ : Bleaching by $C l_{2}$ is temporary due to the process of oxidation in the presence of moisture:
$C l_{2} + H_{2} O \to 2 H C l + [O]$ (nascent)
Colour material $+ [O] \to$ Colourless

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