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Question

Bond order of N+2,N2 and N2 will be

A
2.5,2.5 and 3 respectively
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B
2,2.5 and 3 respectively
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C
3,2.5 and 3 respectively
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D
2.5,2.5 and 2.5 respectively.
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Solution

The correct option is B 2.5,2.5 and 3 respectively
N+2(13):(σ1s2)(σ1s2)(σ2s2)(σ2s2)(π2p2x=π2p2y)(σ2p1z)
B.O.=12×(94)=2.5

N2:(σ1s2)(σ1s2)(σ2s2)(σ2s2)(π2p2x=π2p2y)(σ2pz)2(π2p1x)
B.O.=12×(105)=2.5

N2(14):(σ1s2)(σ1s2)(σ2s2)(σ2s2)(π2p2x=π2p2y)(σ2p2z)

B.O.=12×(104)=3.0

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