Question

Both Arjun and Rahul went for jogging and stopped at a place where kids were playing on a slide as shown below:

Two slides which are directed in the two opposite directions are combined by a vertical stairs in the midway between the two sliders. The lengths of both the slides are same.

Two kids Mia and Anu reached down after sliding down. How much distance has Mia to walk from A to reach Anu who is at B if AC = 5 m and width of the stairs = 1 m?

• A. 10 m
• B. 6 m
• C. 5 m
• D. 11 m

Answer 1

The correct option is D

11 m

If you consider $\Delta$ACE and $\Delta$BDF,

Given that, distances kids can slide on both the sliders are same.

AE = FB

EC = FD (height of the stairs)

$\angle$ACE = $\angle$FDB = ${90}^0$ (Since the stairs are vertical)

$\Rightarrow$ $\Delta$ACE and $\Delta$BDF are congruent using RHS congruence criterion

$\Rightarrow$ AC = DB = 5 m

The distance Mia has to walk to reach Anu = AC + CD + DB
= 5 m + 1 m + 5 m
= 11 m