    Question

# Boyle's, Charles' and Avogadro's results on the different state variables of a gas, can be combined into one "equation of state” known as the ideal gas equation, PV = nRT, where R = 8.514 J/mol-K. Consider the following situation. A mixture of hydrogen and oxygen has volume 2000 cm3, temperature 300 K, pressure 100 kPa and mass 0.76 gms. Calculate the masses of hydrogen and oxygen in the mixture.

A

0.12 gms; 0.64 gms

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B

0.8gms; 0.68 gms

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C

0.24 gms; 0.52 gms

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D

0.16gms; 0.60 gms

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Solution

## The correct option is A 0.12 gms; 0.64 gms Suppose there are n1 moles of hydrogen and n2 moles of oxygen in the mixture. The pressure of the mixture will be - P=(n1RTV)+(n2RTV)=(n1+n2)RTV ⇒100×103Pa=(n1+n2)×[(8.3 JK−1 mol−1)(300 K)200×10−6m−3] ⇒(n1+n2)=0.08 mol .....(i) The mass of the mixture is - (n1×2 gms/mol)+(n2×32 gms/mol)=0.76 gms ⇒(n1+16n2)=0.38 mol. ...(ii) From (i) and (ii), n1=0.06 mol and n2=0.02 mol The mass of hydrogen = 0.06×2 gms=0.12 gms, and the mass of oxygen = 0.02×32 gms=0.64 gms.  Suggest Corrections  0      Similar questions  Related Videos   Equations Redefined
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