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Question

$$...Br{ O }_3^-(aq)+...Br^-(aq)+...H^+(aq)\rightarrow ...Br_2(l)+...H_2O$$
After balancing the above equation. What is the ratio of coefficient $$BrO_3^-$$ to $$Br^-$$ ?


A
1 : 5
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B
1 : 3
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C
1 : 2
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D
1 : 1
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E
2 : 3
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Solution

The correct option is A 1 : 5
 The unbalanced chemical equation is
$$\displaystyle  BrO_3^-(aq)+ Br^-(aq)+ H^+(aq)\rightarrow Br_2(l)+H_2O$$
The oxidation number of bromine increases from -1 (in $$\displaystyle  Br^-$$ ion) to 0 (in $$\displaystyle  Br_2$$ ).
Increase in the oxidation number is 1.
The oxidation number of bromine decreases from +5 (in $$\displaystyle  BrO_3^-$$ ) to 0 (in $$\displaystyle  Br_2$$ ).
Decrease in the oxidation number of bromine is 5.
Balance increase in oxidation number with decrease in oxidation number.
$$\displaystyle  BrO_3^-(aq)+ 5Br^-(aq)+ H^+(aq)\rightarrow 3Br_2(l)+H_2O$$
Hence, the ratio of $$\displaystyle  BrO_3^-$$ to $$\displaystyle  Br^-$$ is 1: 5.

Chemistry

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