  Question

$$...Br{ O }_3^-(aq)+...Br^-(aq)+...H^+(aq)\rightarrow ...Br_2(l)+...H_2O$$ After balancing the above equation. What is the ratio of coefficient $$BrO_3^-$$ to $$Br^-$$ ?

A
1 : 5  B
1 : 3  C
1 : 2  D
1 : 1  E
2 : 3  Solution

The correct option is A 1 : 5 The unbalanced chemical equation is$$\displaystyle BrO_3^-(aq)+ Br^-(aq)+ H^+(aq)\rightarrow Br_2(l)+H_2O$$The oxidation number of bromine increases from -1 (in $$\displaystyle Br^-$$ ion) to 0 (in $$\displaystyle Br_2$$ ).Increase in the oxidation number is 1.The oxidation number of bromine decreases from +5 (in $$\displaystyle BrO_3^-$$ ) to 0 (in $$\displaystyle Br_2$$ ).Decrease in the oxidation number of bromine is 5.Balance increase in oxidation number with decrease in oxidation number.$$\displaystyle BrO_3^-(aq)+ 5Br^-(aq)+ H^+(aq)\rightarrow 3Br_2(l)+H_2O$$Hence, the ratio of $$\displaystyle BrO_3^-$$ to $$\displaystyle Br^-$$ is 1: 5. Chemistry

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