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Question

Brown ppt. (A) dissolve in $$HNO_{3} $$ gives (B) which gives white ppt. (C) with $$NH_{4}OH $$. (C) on reaction with $$HCl$$ gives solution (D) which gives white turbidity on addition of water. What is (D) ? 


A
BiCl3
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B
Bi(OH)3
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C
BiOCl
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D
Bi(NO3)3
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Solution

The correct option is A $$BiCl_{3} $$
$$Bi_{2}S_{3} + 8HNO_{3} \xrightarrow{hot} 2Bi(NO_3)_3 + 3S \downarrow + 2NO + 4H_{2}O $$ 
                    (dil.)
$$Bi(NO_3)_2 + 3NH_{4}OH \rightarrow Bi(OH)_3 \downarrow + 3NH_{4}NO_{3} $$
                                                        (C)
$$Bi(OH)_3 \downarrow + 3HCl \rightarrow BiCl_{3} + 3H_{2}O $$ 
                                                (D) 
$$BiCl_{3} + H_{2}O \rightleftharpoons BiOCl + 2HCl $$ 
     (D)                                  white turbidity 

Chemistry

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