By definition, the total kinetic energy is the sum of translation, rotational and vibrational kinetic energies for monoatomic gases only the translational K.E. is counted. True or False ?

True

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False

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Solution

The correct option is A
True

True, since there is no bonds involved in monatomic gases, there is no scope for vibrational and rotational kinetic energies. So we don't need to think in terms of degree of freedom.

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Similar questions

For monoatomic gases, the total kinetic energy is equal to translational kinetic energy.

We know that, for an ideal monoatomic gas, the total internal energy is a result of the translational kinetic energy only. For the oxygen molecule $O_{2}$ (assume it doesn't oscillate along the bond axis), which rotates as well as translates, choose the correct statement(s) from the following

Q. The pressure of an ideal gas is written as

P = \frac{2 E}{3 V}

. Here E refers to
(a) translational kinetic energy
(b) rotational kinetic energy
(c) vibrational kinetic energy
(d) total kinetic energy.

Q. Three gases

C O_{2}, O_{2}

and

C l_{2}

are at the same temperature. Which of the following relation for the average translation kinetic energy per mole

(E_{k})

is true?

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By definition, the total kinetic energy is the sum of translation, rotational and vibrational kinetic energies for monoatomic gases only the translational K.E. is counted. True or False ?

The correct option is A True True, since there is no bonds involved in monatomic gases, there is no scope for vibrational and rotational kinetic energies. So we don't need to think in terms of degree of freedom.

The correct option is A
True

True, since there is no bonds involved in monatomic gases, there is no scope for vibrational and rotational kinetic energies. So we don't need to think in terms of degree of freedom.