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Question

By how much is 2x − 3y + 4z greater than 2x + 5y − 6z + 2?


Solution

To calculate how much is 2x − 3y + 4z greater than 2x + 5y − 6z + 2, we have to subtract 2x + 5y − 6z + 2 from 2x − 3y + 4z.
Change the sign of each term of the expression that is to be subtracted and then add.

Term to be subtracted = 2x + 5y − 6z + 2
Changing the sign of each term of the expression gives -2x - 5y + 6z - 2.
On adding:
    (2x − 3y + 4z )+(-2x - 5y + 6z - 2 )   
   = 2x − 3y + 4z-2x - 5y + 6z - 2   
   = (2-2)x + (-3-5)y +(4+6)z-2
   = 0-8y+10z-2
   = -8y+10z-2

Mathematics
RS Aggrawal (2020, 2021)
All

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