Question

# By how much is $$\displaystyle x^{4}-4x^{2}y^{2}+y^{4}$$ less than $$\displaystyle x^{4}+8x^{2}y^{2}+y^{4}$$?

A
12x2y2
B
12x2y2
C
12xy
D
12xy

Solution

## The correct option is D $$\displaystyle 12x^{2}y^{2}$$We have to find solution of $$( x^{4}+8x^{2}y^{2}+y^{4})$$ $$-(x^{4}-4x^{2}y^{2}+y^{4})$$ Separating like terms and unlike terms, we get$$=$$ $$x^4 - x^4 +y^4 - y^4 +8x^2y^2-(-4x^2y^2)$$$$=$$ $$8x^2y^2 + 4x^2y^2$$$$=$$ $$12x^2y^2$$Mathematics

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