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Question

By how much is $$\displaystyle x^{4}-4x^{2}y^{2}+y^{4}$$ less than $$\displaystyle x^{4}+8x^{2}y^{2}+y^{4}$$?


A
12x2y2
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B
12x2y2
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C
12xy
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D
12xy
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Solution

The correct option is D $$\displaystyle 12x^{2}y^{2}$$
We have to find solution of
$$( x^{4}+8x^{2}y^{2}+y^{4})$$ $$-(x^{4}-4x^{2}y^{2}+y^{4})$$
Separating like terms and unlike terms, we get
$$=$$ $$x^4 - x^4 +y^4 - y^4 +8x^2y^2-(-4x^2y^2)$$
$$=$$ $$8x^2y^2 + 4x^2y^2$$
$$=$$ $$12x^2y^2$$

Mathematics

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