Question

# By selling two transistors for $$Rs\ 600$$, each a shopkeeper gains $$20$$ percent on one transistor and loses $$20$$ percent on the other. Find :profit or loss percent on the whole.

Solution

## Let the cost price be $$x_1$$ for the transistor gaining $$20\%$$:$$20 \%$$ gain  $$\implies x_1+\dfrac{20x_1}{100}=600$$$$1.2\ x_1=600\implies x_1=500$$Let the cost price be $$x_2$$ for the transistor losing $$20\%$$:$$20 \%$$ loss  $$\implies x_2-\dfrac{20x_2}{100}=600$$$$0.8\ x_2=600\implies x_2=750$$So,Total C.P of both the transistors $$=x_1+x_2= 500 + 750 = ₹\,1250$$Total S.P of both the transistors $$= 600 + 600 = ₹\,1200$$We know thatTotal loss = C.P – S.PSubstituting the values$$= 1250 – 1200$$$$= ₹\,50$$So the loss percent $$= (loss \times 100)/ C.P$$Substituting the values$$= (50 \times 100)/ 1250$$$$= 4\%$$Mathematics

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