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Question

By selling two transistors for Rs 600, each a shopkeeper gains 20 percent on one transistor and loses 20 percent on the other.
Find :
profit or loss percent on the whole.

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Solution

Let the cost price be x1 for the transistor gaining 20%:
20% gain x1+20x1100=600

1.2 x1=600x1=500


Let the cost price be x2 for the transistor losing 20%:
20% loss x220x2100=600

0.8 x2=600x2=750
So,
Total C.P of both the transistors =x1+x2=500+750=1250
Total S.P of both the transistors =600+600=1200

We know that

Total loss = C.P – S.P

Substituting the values

=12501200

=50

So the loss percent =(loss×100)/C.P

Substituting the values

=(50×100)/1250

=4%


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