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Question

By using properties of definite integrals, evaluate the integrals
20x2xdx.

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Solution

Let 20x2xdx.
Also, I=20(2x)2(2x)dx=20(2x)xdx=20(2x12x32)dx=[2x(12)+1(12)+1x(32)+1(32)+1]20=[43x3225x52]20=43.23225.2520=43222542=(8385)2=(402415)2=16215


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