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Question

$$C_1 - H, C_2 - H, C_3 - H$$ and $$C_4 - H$$ homolytic bond dissociation energy is in order:
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A
C2H>C3H>C4H>C1H
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B
C1H>C4H>C2H>C3H
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C
C2H>C3H>C1H>C4H
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D
C1H>C4H>C3H>C2H
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Solution

The correct option is C $$C_1 - H > C_4 - H > C_3 - H > C_2 - H$$
In $$C-H$$ bond, the carbon atom is more electronegative than hydrogen atom. When several alkyl groups are attached to carbon atom (such as $$C_2$$), due to the positive inductive effects of alkyl group, the electronegativity difference between carbon and hydrogen decreases. The hold of the carbon on the shared electron pair of $$C-H$$ bond decreases. The $$C-H$$ bond strength decreases. Hence, the homolytic bond dissociation energy decreases.
The order in which the number of alkyl groups attached to the carbon atom increases is $$C_1 - H < C_4 - H < C_3 - H < C_2 - H$$
The order of the bond dissociation energy is $$C_1 - H > C_4 - H > C_3 - H > C_2 - H$$.

Chemistry

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