Question

# $$C_1 - H, C_2 - H, C_3 - H$$ and $$C_4 - H$$ homolytic bond dissociation energy is in order:

A
C2H>C3H>C4H>C1H
B
C1H>C4H>C2H>C3H
C
C2H>C3H>C1H>C4H
D
C1H>C4H>C3H>C2H

Solution

## The correct option is C $$C_1 - H > C_4 - H > C_3 - H > C_2 - H$$In $$C-H$$ bond, the carbon atom is more electronegative than hydrogen atom. When several alkyl groups are attached to carbon atom (such as $$C_2$$), due to the positive inductive effects of alkyl group, the electronegativity difference between carbon and hydrogen decreases. The hold of the carbon on the shared electron pair of $$C-H$$ bond decreases. The $$C-H$$ bond strength decreases. Hence, the homolytic bond dissociation energy decreases.The order in which the number of alkyl groups attached to the carbon atom increases is $$C_1 - H < C_4 - H < C_3 - H < C_2 - H$$The order of the bond dissociation energy is $$C_1 - H > C_4 - H > C_3 - H > C_2 - H$$.Chemistry

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