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Question

$${ C }_{ 2 }{ H }_{ 5 }I \xrightarrow {alc. KOH} X\xrightarrow { \quad \quad { Br }_{ 2 }\quad \quad  } Y \xrightarrow { \quad \quad KCN\quad \quad  } Z$$;  $$Z$$ is:


A
CH3CH2CN
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B
CNCH2CH2CN
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C
BrCH2CH2CN
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D
BrCH=CHCN
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Solution

The correct option is B $$CN-C{ H }_{ 2 }-C{ H }_{ 2 }-CN$$
$${ C }_{ 2 }{ H }_{ 5 }I \xrightarrow {alc. KOH} CH_2=CH_2\xrightarrow { \quad \quad { Br }_{ 2 }\quad \quad  } CH_2Br-CH_2Br \xrightarrow { \quad \quad KCN\quad \quad  } CH_2CNCH_2CN$$

Chemistry

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