C 2 H 5 I X Y Z- Z is-

The correct option is B CN C H _ 2 C H _ 2 CN C _ 2 H _ 5 I CH_2=CH_2 CH_2Br CH_2Br CH_2CNCH_2CN ...

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Nucleophilic Substitution in Alkyl Halides

C 2 H 5 I X Y...

Question

$C_{2} H_{5} I a l c . K O H - ---- \to X {B r}_{2} - --------- \to Y K C N - ---------- \to Z$ ; $Z$ is:

C H_{3} C H_{2} C N

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C N - C H_{2} - C H_{2} - C N

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B r - C H_{2} - C H_{2} C N

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B r - C H = C H C N

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Similar questions

C | C N H_{2} - C | C N H - C | C N H_{2}

C | H_{2} C N - C | H C N - C | H_{2} C N

The IUPAC name of $N C - C H_{2} - C H | C N - C H_{2} - C N$ is?

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

S_{N} 2

B r - C H_{2} - C H_{2} - B r

N = C - C H_{2} - B r

C H_{3} - C | B r H - C H_{3}

C H_{3} - C H_{2} - B r

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