Ca-2B-6O-11-Na-2CO-3 -A-B-CaCO-3- -A-CO-2 - -B-Na-2CO-3-Solution- -B- Conc- HCI - NaCI-Acid- H-2O- -C-D-Acid -C- -D-CuSO-4 Blue coloured-E-compound-compound -E- is -Cu2O-Cu-BO2-2-CuS-CuSO3-

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Byju's Answer

Standard XII

Chemistry

Borax

Ca_2B_6O_11+N...

Question

$C a_{2} B_{6} O_{11} + N a_{2} C O_{3} F u s e d - -- \to (A) + (B) + C a C O_{3} (A) + C O_{2} \to (B) + N a_{2} C O_{3} Solution (B) + C o n c . H C I \to N a C I + A c i d ↓ H_{2} O (C) S t r o n g l y - ---- \to h e a t e d (D) Acid (C) (D) + C u S O_{4} H e a t e d - ---- \to i n f l a m e Blue coloured (E) compound compound (E) is -$

Cu2O

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CuS

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CuSO3

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Cu(BO2)2

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Solution

The correct option is D
Cu(BO2)2

Compound (A) is - $N a B O_{2}$
Compound (B) is - $N a_{2} B_{4} O_{7}$
Compound (C) is - $H_{3} B O_{3}$
Compound (D) is - $B_{2} O_{3}$
Compound (E) is - $C u (B O_{2})_{2}$

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Similar questions

Some properties of Sulphuric acid are listed below. Choose the property A, B, C or D which is responsible for the reactions (i) to (v). Some properties may be repeated :

A. Acid B. Dehydrating agent

C. Non-volatile acid D. Oxidizing agent

(i) $C_{12} H_{22} O_{11} + n H_{2} S O_{4} \to 12 C + 11 H_{2} O + n H_{2} S O_{4}$

(ii) $S + 2 H_{2} S O_{4} \to 3 S O_{2} + 2 H_{2} O$

(iii) $N a C I + H_{2} S O_{4} \to N a H S O_{4} + H C I$

(iv) $C u O + H_{2} S O_{4} \to C u S O_{4} + H_{2} O$

(v) $N a_{2} C O_{3} + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O + C O_{2}$

A white precipitate can be obtained by adding dilute sulphuric acid to :

(a) $C u S O_{4}$ Solution (b) NaCI Solution (c) $B a C l_{2}$ Solution (d) $N a_{2} S O_{4}$ Solution

Q. Name the type of respiration in which the end products are:
(a) C₂H₅OH and CO₂
(b) CO₂ and H₂O
(c) Lactic acid
Give one example of each case where such a respiration can occur.

$C a_{2} B_{6} O_{11} + N a_{2} C O_{3} F u s e d - -- \to (A) + (B) + C a C O_{3} (A) + C O_{2} \to (B) + N a_{2} C O_{3} Solution (B) + C o n c . H C I \to N a C I + A c i d ↓ H_{2} O (C) S t r o n g l y - ---- \to h e a t e d (D) Acid (C) (D) + C u S O_{4} H e a t e d - ---- \to i n f l a m e Blue coloured (E) compound compound (E) is -$

Q. Match the following:

Column A Types of chemical reaction	Column B Chemical equations
(a) Combination reaction	(i) $C a C O_{3} A \to C a O + C O_{2}$
(b) Decomposition reaction	(ii) $2 H_{2} O E l e c t r i c i t y - ----- \to 2 H_{2} + O_{2}$
(c) Displacement reaction	(iii) $C a O + C O_{2} \to C a C O_{3}$
(d) Analysis reaction	(iv) $F e (s) + C u S O_{4} (a q .) \to F e S O_{4} (a q) + C u (s)$

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Ca2B6O11+Na2CO3Fused−−−→(A)+(B)+CaCO3(A)+CO2→(B)+Na2CO3Solution(B)+Conc.HCI→NaCI+Acid ↓H2O(C)Strongly−−−−−→heated (D) Acid(C)(D)+CuSO4Heated−−−−−→inflameBlue coloured(E) compoundcompound (E) is -

The correct option is D Cu(BO2)2 Compound (A) is - NaBO2 Compound (B) is - Na2B4O7 Compound (C) is - H3BO3 Compound (D) is - B2O3 Compound (E) is - Cu(BO2)2

The correct option is D
Cu(BO2)2

Compound (A) is - $N a B O_{2}$
Compound (B) is - $N a_{2} B_{4} O_{7}$
Compound (C) is - $H_{3} B O_{3}$
Compound (D) is - $B_{2} O_{3}$
Compound (E) is - $C u (B O_{2})_{2}$