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$${ CaCl }_{ 2 }.6{ H }_{ 2 }O\left( s \right) \rightleftharpoons { CaCl }_{ 2 }\left( s \right) +6{ H }_{ 2 }O\left( g \right) { K }_{ 0 }=6.4\times { 10 }^{ -17 }{ atm }^{ 6 }$$. Excess solid $${ CaCl }_{ 2 }.6{ H }_{ 2 }O$$ & $${ CaCl}_{ 2 }$$ are taken in a container containing some water vapours at a pressure of 1.14 torr at a particular temp. Then:


A
CaCl2(s) acts as drying agent under given condition
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B
CaCl2(s) acts as hydroscopic substance given condition
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C
CaCl2.6H2O(s) acts as efflorescent substance.
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D
mass of CaCl2.6H2O(s) increases due to some reaction.
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Solution

The correct option is A $${ CaCl}_{ 2 }\left( s \right) $$ acts as drying agent under given condition
$$P_{water}=1.44torr$$
$$=\dfrac{1.14}{760}\times 100=\dfrac{10^{-2}}{5}atm$$
$$\therefore Q_p=P^6_{H_2O}$$
$$=(\dfrac{10^{-2}}{5})^6=\dfrac{10^{-12}}{5^6}=10^{-18}\times 2^6$$
                                    $$=64\times 10^{-18}$$
$$Q_p > K_p$$
reaction mean in backward direction it act as drying agent.

Chemistry

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