Question

# $${ CaCl }_{ 2 }.6{ H }_{ 2 }O\left( s \right) \rightleftharpoons { CaCl }_{ 2 }\left( s \right) +6{ H }_{ 2 }O\left( g \right) { K }_{ 0 }=6.4\times { 10 }^{ -17 }{ atm }^{ 6 }$$. Excess solid $${ CaCl }_{ 2 }.6{ H }_{ 2 }O$$ & $${ CaCl}_{ 2 }$$ are taken in a container containing some water vapours at a pressure of 1.14 torr at a particular temp. Then:

A
CaCl2(s) acts as drying agent under given condition
B
CaCl2(s) acts as hydroscopic substance given condition
C
CaCl2.6H2O(s) acts as efflorescent substance.
D
mass of CaCl2.6H2O(s) increases due to some reaction.

Solution

## The correct option is A $${ CaCl}_{ 2 }\left( s \right)$$ acts as drying agent under given condition$$P_{water}=1.44torr$$$$=\dfrac{1.14}{760}\times 100=\dfrac{10^{-2}}{5}atm$$$$\therefore Q_p=P^6_{H_2O}$$$$=(\dfrac{10^{-2}}{5})^6=\dfrac{10^{-12}}{5^6}=10^{-18}\times 2^6$$                                    $$=64\times 10^{-18}$$$$Q_p > K_p$$reaction mean in backward direction it act as drying agent.Chemistry

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