Byju's Answer

Standard XII

Chemistry

Percentage Composition

Calcium carbi...

Question

Calcium carbide is made in an electric-furnace by the reaction given below:
$C a O + 3 C ⟶ C a C_{2} + C O$
The crude product is usually $85 %$ $C a C_{2}$ and $15 %$ unreacted $C a O$ .
How much $C a C_{2}$ would this crude product contain?
[Given atomic mass of $C a = 40$ amu, $C = 12$ amu, $O = 16$ amu]

28 %

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34 %

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38 %

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42 %

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Solution

The correct option is B $34 %$
If we suppose that reaction is in equilibrium then the total weight of reactant and product.
$C a O + 3 C \to C a C_{2} + C O$
$56 + 36 + 64 + 28 = 184$
Then the $%$ of $C a C_{2}$ in crude product $= \frac{64}{184} \times 100 = 34.7 %$

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Similar questions

Q. Calcium carbide is made in an electric-furnace by the following reaction :

C a O + 3 C ⟶ C a C O_{2} + C O

The crude product is usually

85 %

C a C_{2}

and

15 %

unreacted

C a O

. How much

C a O

should we start with to produce

450

kg of crude product?
(Given that molecular weight of

C a = 40, C = 12, O = 16

g/mol)

Q. Calcium carbide is made in an electric furnace by the reaction:

C a O + 3 C ⟶ C a C_{2} + C O

The crude product is usually

85 %

C a C_{2}

and

15 %

unreacted

C a O

.
(a)The amount of

C a O

with which we should start to produce

450

kg of crude product is

x

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(b) Amount of

C a C_{2}

which this crude product will contain is

y

kg.
The value of

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in a nearest integer is :

Q. Crude calcium carbide,

C a C_{2}

, is made in an electric furnace by the reaction,

C a O + 3 C \to C a C_{2} + C O

The product contains 64%

C a C_{2}

and 36% unreacted

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(Given that molecular weight of Ca = 40, C =12, O = 16)

Q. How much heat will be required to make

2 k g

of calcium carbide

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according to the following reaction?

C a O (s) + 3 C (s) \to C a C_{2} + C O (g)

The heats of formation of

C a O (s), C a C_{2} (s)

and

C O (g)

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- 151.6, - 14.2, - 26.4 k c a l

respectively.

C a C_{2} + H_{2} O \to C a O + H C \equiv C H

n (C H \equiv C H) + n H_{2} \to - (C H_{2} - C H_{2})_{n} -

Polyethylene can be produced from calcium carbide according to the given sequence of reactions.
The mass of polyethylene that can be produced from

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Calcium carbide is made in an electric-furnace by the reaction given below:CaO+3C⟶CaC2+COThe crude product is usually 85% CaC2 and 15% unreacted CaO. How much CaC2 would this crude product contain? [Given atomic mass of Ca=40 amu, C=12 amu, O=16 amu]

The correct option is B 34%If we suppose that reaction is in equilibrium then the total weight of reactant and product.CaO+3C→CaC2+CO56+36+64+28=184Then the % of CaC2 in crude product =64184×100=34.7%

The correct option is B $34 %$
If we suppose that reaction is in equilibrium then the total weight of reactant and product.
$C a O + 3 C \to C a C_{2} + C O$
$56 + 36 + 64 + 28 = 184$
Then the $%$ of $C a C_{2}$ in crude product $= \frac{64}{184} \times 100 = 34.7 %$