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Question

Calcium lactate is a salt of a weak organic acid and represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.13 mole of this salt in 0.50l litre solution. The pOH of this solution is 5.60. Assuming a complete dissociation of salt, calculate Ka of the lactic acid.

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Solution

Ca(Lac)2Ca2++2Lac
0.13×2M 2×2×0.13M
Lac+H2OHLac+OH
At equi. (0.52x) x x
Kh=x2(0.52x)=x20.52
[OH]=105.6=2.51×106=x
Kh=251×106×2.51×1060.52=12.12×1012
Ka=KwKh=101412.12×1012=8.26×104

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