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Question

Calculate ΔfHICl(g) from the data
ΔHdissociationCl2(g)=57.9Kcalmol1
ΔHdissociationI2(g)=36.1Kcalmol1
ΔHdissociationICl(g)=50.5Kcalmol1
ΔHdissociationI2(g)=15.0Kcalmol1

A
ΔH=4Kcalmol1
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B
ΔH=4Kcalmol1
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C
ΔH=16Kcalmol1
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D
None of these
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Solution

The correct option is A ΔH=4Kcalmol1
The balanced chemical equation for the formation of ICl is as shown.
12Cl2(g)+12I2(s)ICl(g).....ΔfH=?
The balanced chemical equations for the dissociation and sublimation are as shown.
1/21/21/2⎪ ⎪ ⎪⎪ ⎪ ⎪I2(g)2I(g);ΔH1=36.1×1/2Cl2(g)2Cl(g);ΔH2=57.9×1/2I2(s)I2(g)+Cl(g);ΔH3=15.0×1/2ICl(g)I(g)+Cl(g);ΔH4=50.5
The enthalpy change for the formation of ICl(g) is
ΔH=(ΔH1+ΔH2+ΔH3)ΔH4
=12(36.1+57.9+15.0)50.5
=4Kcalmol1

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