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Question

Calculate E values of the following reactions.
2Ag+Zn2+2Ag++Zn

Given that: EAg+/Ag=0.80V,EZn2+/Zn=0.76V

A
1.10V
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B
1.10V
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C
1.56V
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D
1.56V
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Solution

The correct option is C 1.56V
EAg+/Ag=0.80V

Ag++eAg;E=+0.80V - (1)

Zn2++2eZn;E=0.76V - (2)

Inverting (1) and multiply with 2,

2Ag2Ag++2e;E=0.80V - (3)

ΔG2=nFE2=2F(0.76V)

ΔG3=nFE3=2F(0.80V)

ΔGr=ΔG2+ΔG3=2F(1.56V)=2FEr

Er=1.56V

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