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Question

Calculate energy of 2 moles of photons of radiation whose frequency is 5×1014 Hz

A
3.313×1019J
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B
6.626×1019J
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C
3990.2 kJ mol1
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D
6790.2 kJ mol1
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Solution

The correct option is C 3990.2 kJ mol1
Energy (E) of one photon = E = hv

Where, h=6.626×1034J s
E=5×1014 Hz×6.626×1034J s=3.313×1019J
Energy of 2 mole of photon = 3.313×1019J×2×6.022×1023 mol1
=3990.2 kJ mol1


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