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Question

Calculate molality of 2.5 g of ethanoic acid [CH3COOH] in 75 g of benzene.

A
0.551 mol kg1
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B
0.556 mol kg1
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C
0.558 mol kg1
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D
0.552 mol kg1
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Solution

The correct option is B 0.556 mol kg1

MW of CH3COOH=60gmol1

m=w2×1000Mw2×w1=2.5g×100060gmol1×75=0.556 mol kg1


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