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Coagualation of Lyophilic Sols

calculate mol...

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calculate molarity of cuprous and sulphate ion when 10 ampere current is passed for 9.65 sec through 400 ml of 0.8 M coppersulphate solution?

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Q. A current of

1.40

ampere is passed through

500

0.180

M solution of zinc sulphate for

200

seconds. The molarity of

Z n^{2 +}

ions after deposition of zinc is:

Q. A current of

9.65

ampere is passed through

0.2 M

500

ml aqueous solution of

C u S O_{4}

using Cu-electrode for

300 s e c

[C u^{+ 2}]

concentration in the resulting solution, if volume of solutions remains constant.

Q. A current of

1.70

ampere is passed through

300 m L

0.160 M

solution of zinc sulphate for

230

seconds with a current efficiency of

90

per cent. Find out the molarity of

Z n^{2 +}

ions after the deposition of zinc. Assume the volume of the solution to remain constant during electrolysis.

Q. A current of 0.965 ampere is passed through 500 ml of 0.2 M solution of

Z n S O_{4}

for 10 minutes. The molarity of

Z n^{2 +}

after deposition of zinc is:

9.65

ampere is passed through the aqueous solution

N a C l

using suitable electrodes for

1000 s

. The amount of

N a O H

formed during electrolysis is:

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