Question

Calculate no. of ions, atoms, protons, electrons in $3g$ $C{O}_3^{2-}$.

Answer 1

$3$g of ${CO}_3^{2-}\equiv \frac{3g}{60g{mol}^{-1}}=0.05$ mole

$\therefore$ no. of ions $=0.05\times 6.023\times {10}^{23}=0.3\times {10}^{23}$

no. of atoms $=0.3\times {10}^{23}\times 4=1.2\times {10}^{23}$

no. of protons $=0.3\times {10}^{23}\times (12+3\times 16)$

$=18\times {10}^{23}$

no. of electrons $=0.3\times {10}^{23}\times (12+3\times 16+2)$

$=18.6\times {10}^{23}$