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# Calculate the amount of ${\mathrm{CO}}_{2}$ that could be produced when 1) 1 mole of Carbon is burnt in the air 2) 1 mole of Carbon is burnt in 16 grams of ${\mathrm{O}}_{2}$ 3) 2 moles of Carbon is burnt in 16 gram of ${\mathrm{O}}_{2}$

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## Step 1: Calculation of the amount of Carbon dioxide(${\mathrm{CO}}_{2}$) When 1 mole of Carbon is burnt in the air$C+{O}_{2}\to C{O}_{2}$1 mole of Carbon produces 1 mole of ${\mathrm{CO}}_{2}$ which is 44g of ${\mathrm{CO}}_{2}$ as the molar mass of ${\mathrm{CO}}_{2}$ is 44 g.1 mole of Carbon is burnt in 16g of Dioxygen( ${\mathrm{O}}_{2}$) 32g of ${\mathrm{O}}_{2}$ = 44g of ${\mathrm{CO}}_{2}$1g of ${\mathrm{O}}_{2}$ = $\frac{44}{32}$16g of ${\mathrm{O}}_{2}$ = $\frac{44}{32}×16$ 16g of ${\mathrm{O}}_{2}$ = 22g of CO2 in one mole2 moles of Carbon burnt in 16g of Dioxygen (${\mathrm{O}}_{2}$) will produce $22×2$ g of ${\mathrm{CO}}_{2}$.2 moles of Carbon burnt in 16g of Dioxygen (${\mathrm{O}}_{2}$) will generate 44 g of ${\mathrm{CO}}_{2}$.  Suggest Corrections  41      Similar questions  Related Videos   Stoichiometry of a Chemical Reaction
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