Question

Calculate the amount of crystalline oxalic acid (equivalent weight = $63\text{g/eq.}$) required to prepare 250 mL of a $\frac{N}{10}$ oxalic acid solution.

• A. $0.158\text{g}$
• B. $1.575\text{g}$
• C. $15.75\text{g}$
• D. $6.348\text{g}$

Answer 1

The correct option is B $1.575\text{g}$

$\text{Normality}=\frac{\text{gram equivalents}}{\text{total volume of the solution in mL}}\times 1000$
Gram equivalents of oxalic acid = $\frac{0.1}{1000}\times 250=0.025$ equivalent
Number of gram equivalents = $\frac{\text{given amount}}{\text{equivalent weight}}$
Amount of oxalic acid required = $0.025\times 63=1.575\text{g}$