Calculate the amount of energy(in kJ) necessary to raise the temperature of $60.0$ g of aluminium from $35^{o} C$ to $55^{o}$ C, Molar heat capacity of aluminium is $24$ $J m o l^{- 1}$ $K^{- 1}$ .

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Solution

1) No.of moles of $A l (m) = \frac{60 g}{(27 g m o l^{- 1})}$

$= 2.22 m o l$

2) Molar heat capacity(c) $= 24 J m o l^{- 1} K^{- 1}$

Rise in temperature $(Δ T) = 55 - 35$

$= 20 K$

3) Heat evolved (q) $= C \times m \times T$

$= (24 J m o l^{- 1} K^{- 1}) \times (2.22 m o l) \times (20 K)$

$= 1065.7 J$

$= 1.06 k J$

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Calculate the amount of energy(in kJ) necessary to raise the temperature of 60.0g of aluminium from 35oC to 55oC, Molar heat capacity of aluminium is 24 Jmol−1 K−1.

1) No.of moles of Al(m)=60g(27gmol−1) =2.22mol 2) Molar heat capacity(c)=24Jmol−1K−1 Rise in temperature (ΔT)=55–35 =20K 3) Heat evolved (q) =C×m×T =(24Jmol−1K−1)×(2.22mol)×(20K) =1065.7J =1.06kJ

Calculate the amount of energy(in kJ) necessary to raise the temperature of $60.0$ g of aluminium from $35^{o} C$ to $55^{o}$ C, Molar heat capacity of aluminium is $24$ $J m o l^{- 1}$ $K^{- 1}$ .