Calculate the amount of ice (in g) that will separate out on cooling a solution containing 31 g of ethylene glycol in 125 g water to $- 9.3^{0} C$ .
$K_{f}$ for water = 1.86 $K m o l^{- 1} k g$

Open in App

Solution

Molar mass of ethylene glycol = 62 g/mol
So, $Δ T_{f} = 9.3 = K_{f} m = 1.86 \times \frac{31 \times 1000}{62 \times W}$ $\Rightarrow W = 100 g$
So, ice separated out = (125 - 100) g = 25 g

Suggest Corrections

Similar questions

- {9.3}^{\circ} C :

[K_{f} f o r w a t e r = 1.86 K m o l^{- 1} k g]

- {9.3}^{o} C

K_{f}

= 1.86 K m o l^{- 1} k g)

- {9.3}^{o} C

[K_{f} = 1.86 K m o l^{- 1}]

50

200

- {9.3}^{o} C

K_{f}

1.86

^{- 1}

The amount of ice that will separate out on cooling a solution containing 50 gram of Ethylene glycol in 200 gram water to -9.3⁰C

(K_f=1.86K/molal)

Join BYJU'S Learning Program